Chemistry
How To Calculate Dilution
Diluting a solution adds solvent without changing how much solute is present. That single fact gives one equation relating the stock solution to the dilute one.
Quick Answer
C1 x V1 = C2 x V2
- C1
- Concentration of the stock solution you are starting with
- V1
- Volume of stock solution you need to measure out
- C2
- Concentration you want to end up with
- V2
- Final volume of the diluted solution
The moles of solute do not change when you add solvent, so the concentration times the volume is the same before and after. To make 100 millilitres of a 0.5 molar solution from 5 molar stock you need 10 millilitres of stock, 90 millilitres of diluent, and the dilution factor is 10.
What Is Dilution?
Dilution is the process of lowering a concentration by adding more solvent. No solute is added and none is removed, so the amount of dissolved material stays exactly the same while the volume it is spread through grows. Everything about the calculation follows from that one conservation fact.
The equation is C1 times V1 equals C2 times V2. Each side is a concentration multiplied by a volume, which works out to moles of solute. The left side counts the moles you take out of the stock bottle and the right side counts the moles in the finished solution, and the two must match because the solute never went anywhere.
Rearranging gives the volume of stock you need: C2 times V2 divided by C1. To prepare 100 millilitres of a 0.5 molar solution from 5 molar stock you need 10 millilitres of stock. The remaining 90 millilitres of the 100 is solvent, which is why the diluent volume is the final volume minus the stock volume.
The dilution factor is the ratio of the two concentrations, stock over final. Going from 5 molar to 0.5 molar is a tenfold dilution, written 1 in 10 or sometimes 10x. The same factor also equals the ratio of final volume to stock volume, which is a useful cross-check because both routes should agree.
It is worth being precise about what a tenfold dilution means, because the wording is genuinely ambiguous in practice. A tenfold dilution made in one step takes one part of stock and adds nine parts of solvent, for a total of ten. Confusing that with a ratio of one to ten, which would give eleven parts in total, is a common and avoidable source of error.
The formula only holds when the units match on both sides. Molarity on the left must be molarity on the right, and millilitres must match millilitres. In practice the volume units cancel, so you can use microlitres on one side and millilitres on the other as long as you are consistent within each side of the equation.
Serial dilution extends the idea over several steps. Each step multiplies the dilution factor, so three tenfold steps give a thousandfold dilution overall. Doing it in stages is far more accurate than trying to pipette a tiny volume of stock directly, because measuring 10 microlitres accurately is harder than measuring 100 microlitres three times.
Temperature matters more than most people expect, because volume changes with temperature while the number of moles does not. A solution made up at one temperature and used at another will have a slightly different molarity. Volumetric glassware is calibrated at 20 degrees Celsius, and for work needing four significant figures the difference is real.
Dilution calculations appear constantly in laboratory work: preparing working standards for a calibration curve, reducing a concentrated acid to a safe working strength, or bringing an over-range sample into the measurable window of an instrument. In each case the arithmetic is the same, only the framing changes.
One consequence that catches people out is that the pH does not scale linearly with the dilution factor. Because pH is a logarithmic scale, a tenfold dilution of a strong acid raises the pH by exactly one unit. A hundredfold dilution raises it by two. Doubling the volume, on the other hand, barely moves it.
Formula
C1 x V1 = C2 x V2
The moles of solute are conserved, so concentration times volume is unchanged by adding solvent.
| Symbol | Meaning | Unit | Notes |
|---|---|---|---|
| C1 | Stock concentration | mol/L | The concentration you are diluting from. |
| V1 | Stock volume | L | How much of the stock solution to measure out. |
| C2 | Final concentration | mol/L | The concentration you want. |
| V2 | Final volume | L | The total volume of the diluted solution. |
V1 = (C2 x V2) / C1
The rearranged form of the dilution equation, giving the volume to pipette straight away.
| Symbol | Meaning | Unit | Notes |
|---|---|---|---|
| V1 | Stock volume | L | The volume of stock solution to measure out. |
| C2 | Final concentration | mol/L | The concentration you want. |
| V2 | Final volume | L | The total volume of the diluted solution. |
| C1 | Stock concentration | mol/L | The concentration you are diluting from. |
DF = C1 / C2
How many times weaker the final solution is. It also equals the final volume divided by the stock volume.
| Symbol | Meaning | Unit | Notes |
|---|---|---|---|
| DF | Dilution factor | ratio | The fold change in concentration, such as 10 for a tenfold dilution. |
| C1 | Stock concentration | mol/L | The concentration you are diluting from. |
| C2 | Final concentration | mol/L | The concentration you want. |
How To Calculate Dilution
- 1
Write down the stock concentration and the one you want
Call the stock C1 and the target C2, and make sure both are in the same unit. Five molar stock diluted to 0.5 molar is a clear pair; mixing molarity with millimolar is not.
- 2
Fix the final volume you want to prepare
This is V2, the total volume of the finished solution including the solvent. Wanting 100 millilitres of dilute solution means V2 is 100, not 90.
- 3
Solve for the stock volume
Multiply C2 by V2 and divide by C1. Half a mole per litre times 100 millilitres, divided by 5 moles per litre, gives 10 millilitres of stock.
- 4
Subtract to find the diluent
Take the stock volume away from the final volume. Ninety millilitres of solvent brings 10 millilitres up to the 100 millilitres you wanted. Adding 100 millilitres of solvent instead would overshoot.
- 5
Check with the dilution factor
Divide the stock concentration by the final one. Five divided by 0.5 is 10, so this is a tenfold dilution, and the final volume divided by the stock volume should also come to 10. Both routes agreeing is a good sign the arithmetic is right.
Examples
Example 1: Preparing 100 millilitres of 0.5 molar from 5 molar stock
- Stock concentration
- 5 mol/L
- Target concentration
- 0.5 mol/L
- Target volume
- 100 mL
| Step | Calculation | Result |
|---|---|---|
| Stock volume needed | 0.5 x 100 / 5 | 10 |
| Diluent volume | 100 - 10 | 90 |
| Dilution factor | 5 / 0.5 | 10 |
Result: Turning 100 millilitres of 5 molar stock into a 0.5 molar solution takes 10 millilitres of stock made up to volume with 90 millilitres of diluent, a tenfold dilution.
Example 2: A 40 fold dilution into 500 millilitres
- Stock concentration
- 2 mol/L
- Target concentration
- 0.05 mol/L
- Target volume
- 500 mL
| Step | Calculation | Result |
|---|---|---|
| Stock volume needed | 0.05 x 500 / 2 | 12.5 |
| Diluent volume | 500 - 12.5 | 487.5 |
| Dilution factor | 2 / 0.05 | 40 |
Result: A 500 millilitre flask of 0.05 molar solution made from 2 molar stock needs 12.5 millilitres of stock and 487.5 millilitres of diluent, which is a 40 fold dilution.
Example 3: Halving a 10 molar solution to 50 millilitres
- Stock concentration
- 10 mol/L
- Target concentration
- 1 mol/L
- Target volume
- 50 mL
| Step | Calculation | Result |
|---|---|---|
| Stock volume needed | 1 x 50 / 10 | 5 |
| Diluent volume | 50 - 5 | 45 |
| Dilution factor | 10 / 1 | 10 |
Result: Preparing 50 millilitres of 1 molar solution from 10 molar stock takes 5 millilitres of stock diluted with 45 millilitres of solvent, a tenfold dilution.
Calculator
Stock volume needed
10
- Diluent volume
- 90
- Dilution factor
- 10
- Stock as a share of the final volume
- 10.00%
Values update as you type. This calculator covers the single scenario its formula assumes — see Common Mistakes for what it leaves out.
Prefer a full-width tool? Open the Dilution calculator page.
Common Mistakes
Treating the diluent volume as the final volume
The final volume is stock plus diluent, not diluent alone. Adding 100 millilitres of solvent to 10 millilitres of stock produces 110 millilitres of a weaker solution than intended, and the error is invisible unless you check the dilution factor.
Mixing concentration units across the equation
Both concentrations must be in the same unit and both volumes must be in the same unit. Molarity on one side and millimolar on the other shifts the answer by a factor of a thousand without any warning sign.
Reading a tenfold dilution as a one to ten ratio
A tenfold dilution is one part stock plus nine parts solvent, making ten parts in total. A one to ten ratio would be one part in eleven. The wording is genuinely ambiguous in casual use, so it pays to state the parts explicitly.
Forgetting that pH does not scale with the dilution factor
pH is logarithmic, so a tenfold dilution of a strong acid changes the pH by one unit, not by a factor of ten. Diluting by volume and expecting the pH to fall proportionally produces a wildly wrong answer.
Assuming the volumes simply add
Real solutions can contract or expand slightly on mixing, because the solute and solvent molecules interact. For teaching problems the volumes add exactly, but a precise analytical preparation makes the solution up to the mark in a volumetric flask rather than trusting the sum.
Measuring a tiny stock volume in one step
Pipetting 10 microlitres accurately is far harder than pipetting 100 microlitres three times. Serial dilution trades extra steps for much better precision, which is why it is standard practice rather than an optional refinement.
FAQ
What is the dilution formula?
C1 times V1 equals C2 times V2, where C1 and V1 describe the stock solution and C2 and V2 describe the diluted one. It says the moles of solute are unchanged, which is exactly what happens when you add solvent.
How much stock do I need to make a dilute solution?
Multiply the target concentration by the target volume, then divide by the stock concentration. To make 100 millilitres of 0.5 molar from 5 molar stock you need 10 millilitres of stock, made up to the mark with diluent.
How much diluent should I add?
Subtract the stock volume from the final volume. Ten millilitres of stock in a 100 millilitre flask needs 90 millilitres of diluent. Adding 100 millilitres instead would give a total of 110 and a weaker solution than planned.
What does a tenfold dilution mean?
One part of stock combined with nine parts of solvent, making ten parts in total. The concentration falls by a factor of 10. It is not the same as a one to ten ratio, which would be one part in eleven.
How does dilution affect pH?
Because pH is a logarithmic scale, a tenfold dilution of a strong acid raises the pH by one unit and a hundredfold dilution raises it by two. Doubling the volume barely changes it at all.
Why is serial dilution more accurate than one big dilution?
Because each step uses a comfortably measurable volume. Measuring 10 microlitres accurately is difficult, while measuring 100 microlitres three times in a row is easy, and the errors compound far less than the single tiny measurement.
References
- [1]Wikipedia, Serial dilution — https://en.wikipedia.org/wiki/Serial_dilution
- [2]Wikipedia, Molar concentration — https://en.wikipedia.org/wiki/Molar_concentration
- [3]Wikipedia, Concentration — https://en.wikipedia.org/wiki/Concentration
- [4]Khan Academy, Solution — https://www.khanacademy.org/science/chemistry/states-of-matter-and-intermolecular-forces/mixtures-and-solutions/a/mixtures-and-solutions