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Chemistry

How To Calculate Percent Yield

Percent yield compares what a reaction actually produced with what the balanced equation says it should have produced. It is the standard measure of how well a synthesis went.

Quick Answer

percent yield = actual mass / theoretical mass x 100

actual
The mass of product actually collected
theoretical
The mass the balanced equation predicts
purity
The fraction of the product that is the compound you want

Divide the mass of product you collected by the mass the equation predicts, then multiply by one hundred. A reaction that should give 180 grams and gives 162 grams runs at 90 percent yield, and 162 grams of 95 percent purity counts as 85.5 percent of the theoretical mass.

What Is Percent Yield?

Percent yield is a ratio, so it has no units. It is reported as a percentage by multiplying the ratio by one hundred, which is why 162 over 180 becomes 90 percent.

The theoretical yield comes from the balanced equation and the limiting reagent. Convert the mass of each reactant to moles, find which runs out first, and use the mole ratio to get the moles of product.

Real yields are almost always below one hundred percent because product is lost at every transfer, filtration and drying step. A hundred percent yield in a report usually means the product was not dried.

Purity is a separate correction. If the crude product is only ninety five percent pure, the useful mass is ninety five percent of what you weighed, and the yield falls accordingly.

Side reactions are the other main loss. When the starting material can follow two pathways, some of it is diverted into the product you did not want, and that fraction never appears in the yield.

Incomplete reactions leave reactant behind. If the equilibrium does not favour the products, no amount of patience will push the yield to the theoretical value.

Industrial processes aim for high yields but also for high atom economy. A reaction with mediocre yield but almost no waste can be greener than a clean reaction that produces kilograms of byproduct.

The theoretical yield assumes perfect stoichiometry and complete conversion. Errors in the limiting reagent calculation are the most common reason a yield comes out above one hundred percent.

Worked up yields above one hundred percent almost always mean the product contains residual solvent or water, so the measured mass is inflated.

Percent yield is reported alongside percent purity for exactly this reason. One tells you how much of the possible product you made, the other tells you how much of what you made is actually the product.

Percent yield is often reported per step rather than for the whole synthesis. A five step route at ninety percent each gives only 59 percent overall, which is why long routes are designed around the weakest step rather than the strongest.

Catalysts change the rate, not the equilibrium. A beautifully catalysed reaction still stops at the same equilibrium position, so the ceiling on the yield is set by thermodynamics rather than by the catalyst.

Yield is not the only figure of merit. A route that makes two products together with a clean separation may beat a higher yielding route that needs an expensive chromatography step or a hazardous reagent.

The theoretical yield calculation assumes the reaction goes exactly as written. Any competing hydrolysis, oxidation or polymerisation of the intermediate silently removes starting material from the main pathway.

Formula

percent yield = actual mass / theoretical mass x 100

Formula page →

The fraction of the theoretical product actually isolated.

SymbolMeaning
actual massActual mass
theoretical massTheoretical mass
percent yieldPercent yield

theoretical mass = moles of limiting reagent x mole ratio x product molar mass

Formula page →

How the theoretical mass is obtained from the balanced equation.

SymbolMeaning
n limitingMoles of limiting reagent
rMole ratio
M productProduct molar mass

How To Calculate Percent Yield

  1. 1

    Work out the theoretical mass

    Convert the limiting reagent to moles, apply the mole ratio from the balanced equation, and multiply by the molar mass of the product.

  2. 2

    Weigh the dry product

    Dry the product first, then weigh it. Residual solvent inflates the mass and pushes the apparent yield above the true value.

  3. 3

    Correct for purity

    If the crude product is not pure, multiply the weighed mass by the purity fraction. Ninety five percent purity leaves ninety five percent of the mass as useful product.

  4. 4

    Divide and multiply by one hundred

    162 grams divided by 180 grams is 0.9, and multiplying by one hundred gives a yield of 90 percent.

  5. 5

    Sanity check the number

    Anything above one hundred percent means an error somewhere, most often wet product or a wrong limiting reagent.

Examples

Example 1: A reaction that should give 180 grams and gives 162 grams

Theoretical mass
180
Actual mass
162
Purity
100%
Molar mass
90
StepCalculationResult
Purity fraction100 / 1001
Effective actual mass162 x 1162
Ratio to theory162 / 1800.9
Percent yield0.9 x 10090
Mass short of theory162 - 180-18
Moles of product162 / 901.8

Result: The reaction runs at 90 percent yield. It fell short by 18 grams of theory, and the 1.8 moles of product collected account for nine tenths of what the balanced equation predicted.

Example 2: A small scale reaction with an 82 percent yield

Theoretical mass
50
Actual mass
41
Purity
100%
Molar mass
100
StepCalculationResult
Purity fraction100 / 1001
Effective actual mass41 x 141
Ratio to theory41 / 500.82
Percent yield0.82 x 10082
Mass short of theory41 - 50-9
Moles of product41 / 1000.41

Result: Collecting 41 grams against a theoretical 50 grams is an 82 percent yield. The shortfall is 9 grams, and 0.41 moles of product were isolated, which is a good result for a reaction worked up on this scale.

Example 3: Crude product at 97 percent purity

Theoretical mass
200
Actual mass
171
Purity
97%
Molar mass
76
StepCalculationResult
Purity fraction97 / 1000.97
Effective actual mass171 x 0.97165.87
Ratio to theory165.87 / 2000.82935
Percent yield0.82935 x 10082.935
Mass short of theory165.87 - 200-34.13
Moles of product171 / 762.25

Result: Weighing 171 grams of 97 percent pure crude product is the same as 165.87 grams of pure compound, so the yield is 82.935 percent. Before the purity correction the number would have looked like 85.5 percent, and the 2.25 moles collected still leave 34.13 grams short of theory.

Calculator

Percent yield

85.50%

Mass short of theory
-26.1
Moles of product
1.8
Yield before purity correction
90.00%

Values update as you type. This calculator covers the single scenario its formula assumes — see Common Mistakes for what it leaves out.

Prefer a full-width tool? Open the Percent Yield calculator page.

Common Mistakes

  • Comparing against the wrong limiting reagent

    The theoretical yield comes from whichever reagent runs out first, not from the one with the most dramatic numbers. Using the excess reagent inflates the theoretical mass and makes any real yield look poor.

  • Forgetting to dry the product

    Residual solvent adds mass without adding product. A yield above one hundred percent is nearly always wet product rather than a remarkable reaction.

  • Skipping the purity correction

    Crude product is rarely pure. Weighing 171 grams of 97 percent material as though it were pure overstates the yield by more than three points.

  • Multiplying by one hundred twice

    The ratio is already a fraction between zero and one. Multiplying it by one hundred once gives a percentage, and doing it again gives a number no one can interpret.

  • Quoting a yield from an unbalanced equation

    The mole ratio comes from the balanced equation. An unbalanced equation silently changes the theoretical mass and therefore the yield.

  • Treating yield as a measure of rate

    Percent yield says nothing about speed. A reaction that gives ninety percent in three weeks may be far less useful than one that gives sixty percent in an hour.

FAQ

What is percent yield?

It is the actual mass of product divided by the theoretical mass, multiplied by one hundred. It measures how completely a reaction delivered the product the equation promised.

Can percent yield be above one hundred percent?

Only through error. Wet product, impurities that add mass, or a wrong limiting reagent all push the apparent yield above the theoretical value.

How do I correct for purity?

Multiply the collected mass by the purity fraction before dividing. Ninety five percent purity means 162 grams of crude product is 153.9 grams of useful compound.

What is a good percent yield?

It depends on the reaction. Syntheses with many steps often report thirty to sixty percent per step, while a simple precipitation can reach the high nineties.

Does percent yield include side products?

No. Side products reduce the yield of the desired compound but are not counted in it. Percent selectivity is the separate measure for that.

Why is my yield lower than my lab partner's?

Losses happen during transfer, filtration and washing. Small differences in technique move the yield by several points without either of you making an error.

References

  1. [1]Wikipedia, Yield (chemistry) — https://en.wikipedia.org/wiki/Yield_(chemistry)
  2. [2]Wikipedia, Limiting reagent — https://en.wikipedia.org/wiki/Limiting_reagent
  3. [3]Wikipedia, Atom economy — https://en.wikipedia.org/wiki/Atom_economy