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Physics

How To Calculate Potential Energy

Lifting an object stores energy in the gravitational field. Mass, gravity and height are all it takes to work out how much.

Quick Answer

PE = m x g x h

PE
Gravitational potential energy stored, in joules
m
Mass of the object, in kilograms
g
Gravitational acceleration, about 9.80665 metres per second squared
h
Height above the reference point, in metres

Multiply the mass in kilograms by the gravitational acceleration and by the height lifted. A 10 kilogram mass raised 20 metres stores 1961.33 joules, falls for 2.0196199771025523 seconds if released, and reaches the ground at 19.80570624845274 metres per second with the same 1961.33 joules as kinetic energy.

What Is Potential Energy?

Gravitational potential energy is the energy an object has because of its position in a gravitational field. Lift something up and you have done work against gravity; that work is stored and can be released later by letting the object fall. The higher it goes, the more is stored.

The formula is mass times gravity times height, usually written PE equals m g h. All three factors must be present. Doubling any one of them doubles the energy, which makes the relationship unusually easy to reason about: this is a linear formula, unlike kinetic energy, which depends on the square of speed.

The height is measured from a reference point you choose, and that choice is arbitrary as long as you are consistent. Energy is only ever meaningful as a difference, so measuring from the floor, from the table or from sea level all give the same answer for the same change in height. What you cannot do is measure the top from one reference and the bottom from another.

Gravity near the Earth's surface is about 9.80665 metres per second squared, and this single number is what makes the formula usable without any calculus. It is not truly constant; it falls off with distance from the centre of the Earth, but over the heights a building or a crane deals with, the change is far too small to matter.

The unit is the joule, which is one kilogram metre squared per second squared. Multiplying kilograms by metres per second squared by metres produces exactly those dimensions, so the units come out right without any fudge factors. A joule is a small amount of energy, roughly what it takes to lift an apple one metre.

Releasing the object converts the stored potential energy into kinetic energy. Because the total is conserved, the potential energy at the top equals the kinetic energy at the bottom, provided nothing is lost to air resistance. That equality is the fastest route to the impact speed: set m g h equal to half m v squared and the mass cancels, leaving v equals the square root of two g h.

The mass cancelling out of the fall is a striking result. A heavy object and a light one dropped from the same height hit the ground at the same speed, because the extra energy stored by the heavier object is exactly offset by the extra energy needed to move its greater mass. Air resistance is the only reason everyday objects behave differently.

Because the height appears to the first power, potential energy grows steadily with height rather than explosively. Raising a load to twice the height stores twice the energy. This is why the energy needed to lift something is so predictable, and why cranes and lifts can be specified with simple arithmetic.

The reference point is not always the ground. In problems involving a table, the natural zero is the table top; in problems involving a pendulum, it is the lowest point of the swing. Choosing the reference so that the motion you care about happens at positive heights keeps the arithmetic positive and the signs easy to follow.

The formula assumes gravity is the only force doing work on the object. If something else is also lifting it, such as a motor or a hand, the energy stored is still m g h but the energy supplied is larger, because some is lost to friction and some goes into kinetic energy if the object is still moving. Separating stored energy from supplied energy is the step most often skipped.

Formula

PE = m x g x h

Mass times gravitational acceleration times the height above the reference point.

SymbolMeaning
E_pPotential energy
mMass
gGravitational acceleration
hHeight

v = sqrt(2 x g x h)

Setting the stored potential energy equal to the kinetic energy at the bottom cancels the mass, leaving the speed in terms of height alone.

SymbolMeaning
vImpact speed
gGravitational acceleration
hHeight

t = sqrt(2 x h / g)

The time a dropped object takes to reach the ground, again independent of its mass.

SymbolMeaning
tTime to fall
hHeight
gGravitational acceleration

How To Calculate Potential Energy

  1. 1

    Weigh the object in kilograms

    Grams must be divided by 1000 before they go into the formula. A 500 gram ball is 0.5 kilograms, and using 500 would inflate the answer a thousandfold.

  2. 2

    Measure the height from a reference point you have chosen

    Any reference works as long as both ends of the motion use the same one. A 20 metre lift measured from the ground stores the same energy as the same lift measured from a platform, provided the platform is the zero both times.

  3. 3

    Multiply mass by gravity

    Ten kilograms times 9.80665 metres per second squared gives 98.0665 newtons, which is simply the object's weight. It is worth pausing here because the weight is a force and the next step turns it back into energy.

  4. 4

    Multiply by the height

    98.0665 newtons times 20 metres gives 1961.33 joules. The newton-metre is the same as the joule, which is why a force multiplied by a distance produces an energy.

  5. 5

    Use the height again for the fall

    If the object is released, the impact speed is the square root of two g h, here 19.80570624845274 metres per second, and the fall takes 2.0196199771025523 seconds. Both come from the same height and neither needs the mass.

Examples

Example 1: A 10 kilogram mass lifted 20 metres

Mass
10 kg
Height
20 m
Gravity
9.80665 m/s^2
StepCalculationResult
Impact speed if releasedsqrt(2 x 9.80665 x 20)19.80570624845274
Time to fallsqrt(2 x 20 / 9.80665)2.0196199771025523
Kinetic energy at impact0.5 x 10 x 19.80570624845274 x 19.805706248452741961.3299999999995
Weight10 x 9.8066598.0665
Potential energy stored98.0665 x 201961.33

Result: A 10 kilogram mass lifted 20 metres stores 1961.33 joules, would fall for 2.0196199771025523 seconds, and would land at 19.80570624845274 metres per second carrying the same 1961.33 joules as kinetic energy.

Example 2: A half kilogram ball raised two metres

Mass
0.5 kg
Height
2 m
Gravity
9.80665 m/s^2
StepCalculationResult
Impact speedsqrt(2 x 9.80665 x 2)6.2631142413339385
Time to fallsqrt(2 x 2 / 9.80665)0.6386599135621175
Weight0.5 x 9.806654.903325
Potential energy4.903325 x 29.80665

Result: A half kilogram ball raised two metres stores 9.80665 joules, reaches 6.2631142413339385 metres per second if dropped, and takes 0.6386599135621175 seconds to land.

Example 3: A 75 kilogram climber one and a half metres up

Mass
75 kg
Height
1.5 m
Gravity
9.80665 m/s^2
StepCalculationResult
Impact speedsqrt(2 x 9.80665 x 1.5)5.424016039799293
Time to fallsqrt(2 x 1.5 / 9.80665)0.5530957095235675
Weight75 x 9.80665735.49875
Potential energy735.49875 x 1.51103.248125

Result: A 75 kilogram climber stepping up one and a half metres gains 1103.248125 joules of potential energy, and would hit 5.424016039799293 metres per second in a fall of 0.5530957095235675 seconds.

Calculator

Potential energy stored

1,961.33

Impact speed if released
19.8057
Time to fall
2.0196
Kinetic energy at impact
1,961.33

Values update as you type. This calculator covers the single scenario its formula assumes — see Common Mistakes for what it leaves out.

Prefer a full-width tool? Open the Potential Energy calculator page.

Common Mistakes

  • Using grams where the formula needs kilograms

    The joule is defined in terms of kilograms, so a mass in grams must be divided by 1000 first. Forgetting this inflates the answer by a factor of a thousand and produces an energy figure that is far too large for the object described.

  • Mixing reference points between the top and the bottom

    Height is a difference, so both ends must be measured from the same zero. Taking the top from sea level and the bottom from the floor of the room gives a height that is not the distance the object actually moved.

  • Assuming the stored energy equals the energy supplied

    If a motor or a person lifts something, the energy supplied is larger than m g h, because some goes into friction and some into kinetic energy if the object is still moving at the top. The formula gives the energy stored, not the energy paid for.

  • Using the object's speed instead of the height for the fall

    The impact speed and the fall time both come from the height alone, not from the mass or the stored energy. Trying to derive the speed from the energy works, but only because the mass cancels, and doing it directly is much less error prone.

  • Believing heavier objects fall faster

    The mass cancels out of the fall entirely, so a heavy object and a light one dropped from the same height land at the same speed and at the same time in a vacuum. Everyday differences come from air resistance, which is a force rather than a property of gravity.

  • Treating the reference point as physically meaningful

    The height is measured from wherever you like, and only differences matter. A negative height is perfectly legal and simply means the object is below the reference. Insisting that the height must be positive leads to unnecessary sign confusion.

FAQ

What is the formula for gravitational potential energy?

Potential energy equals mass times gravitational acceleration times height, written PE = m g h. A 10 kilogram mass lifted 20 metres stores 1961.33 joules using the standard gravity of 9.80665 metres per second squared.

Does the height need to be measured from the ground?

No. Any reference point works, as long as you use the same one for both ends of the motion. Only the change in height matters, so measuring from a table or a platform gives exactly the same stored energy for the same lift.

How fast does an object hit the ground?

The impact speed is the square root of two g h. From 20 metres that is 19.80570624845274 metres per second. Notice that the mass does not appear, so a heavy object and a light one land at the same speed in the absence of air resistance.

Why does mass cancel out of the fall?

Because the energy stored is proportional to mass and the kinetic energy needed is also proportional to mass. Setting m g h equal to half m v squared removes the mass from both sides, leaving the speed in terms of height alone.

What unit is potential energy measured in?

The joule. Multiplying kilograms by metres per second squared gives newtons, and multiplying newtons by metres gives joules, so the units of m g h work out without any conversion factor.

How long does it take an object to fall a given height?

The time is the square root of two h divided by g. From 20 metres that is 2.0196199771025523 seconds. Like the impact speed, it does not depend on the mass, only on the height and the strength of gravity.

References

  1. [1]Wikipedia, Potential energy — https://en.wikipedia.org/wiki/Potential_energy
  2. [2]Wikipedia, Gravitational energy — https://en.wikipedia.org/wiki/Gravitational_energy
  3. [3]Wikipedia, Kinetic energy — https://en.wikipedia.org/wiki/Kinetic_energy
  4. [4]Wikipedia, Standard gravity — https://en.wikipedia.org/wiki/Standard_gravity