How the gear ratio works
The gear ratio is the ratio of teeth on the driven gear to teeth on the driving gear:
Ratio = Ndriven ÷ Ndriver
Output speed divides by the ratio and ideal output torque multiplies by it (minus losses):
RPMout = RPMin ÷ Ratio Tout ≈ Tin × Ratio × η
The efficiency factor η captures mesh losses — a single spur mesh runs roughly 98–99%, each additional stage subtracts again, and worm gears can drop to 50–90%. Power is conserved apart from those losses: you can never get more power out than in, only trade speed for torque along the way.
Worked example
A 12-tooth pinion drives a 36-tooth gear at 1800 RPM. Ratio = 36 ÷ 12 = 3:1. Output speed = 1800 ÷ 3 = 600 RPM. A 10 N·m input torque yields roughly 29.4 N·m at the output with 98% mesh efficiency (10 × 3 × 0.98). This 3:1 reduction is why e-bike mid-drives climb steep grades: the motor spins fast with small torque, the gears convert that into wheel torque.
Compound and idler gears
An idler gear between driver and driven changes rotation direction but not the overall ratio. Compound trains multiply: total ratio is the product of each stage's ratio (two 3:1 stages = 9:1). For belt and chain drives the same math applies with sprocket or pulley tooth counts.