Mechanics
How To Calculate A Centripetal Force
Anything moving in a circle needs a force pointing at the centre, and its size depends on speed squared, mass and how tight the turn is.
Quick Answer
F = m x v squared / r
- F
- Centripetal force
- m
- Mass
- v
- Tangential speed
- r
- Radius
Square the speed, multiply by the mass, and divide by the radius. A 150 gram mass swung at 12 m/s on an 80 cm string needs 27 newtons of inward force.
What Is A Centripetal Force?
Centripetal force is the inward force that keeps an object moving on a circular path rather than flying off in a straight line. It is not a new kind of force; it is whatever force happens to be available and pointing at the centre. Tension in a string, friction between tyres and road, and gravity between a satellite and its planet all play the same role.
The formula is mass times velocity squared divided by radius. The speed enters squared, which means doubling the speed quadruples the required force. That is why a corner taken twice as fast needs four times the grip, and why the safe speed for a curve is so much lower than the comfortable speed feels like it should be.
The acceleration that goes with the force is velocity squared over radius, directed inward. This is the centripetal acceleration, and it exists because the direction of the velocity changes even when its magnitude does constant. Velocity is a vector, so changing direction is acceleration, and acceleration always needs a force.
The word centripetal means centre seeking, and the direction is the whole point. The force is perpendicular to the velocity, which is why it does no work: the speed stays the same while the direction keeps turning. A force with any component along the direction of motion would change the speed, which is what happens in a spiral rather than a circle.
The angular velocity form is often more convenient. Since v equals omega r, the force becomes m times omega squared times r. Which version to use depends on how the motion is described: revolutions per second point to the angular form, and metres per second point to the linear form. They always give the same answer, so converting between them is only a matter of convenience.
The revolution period closes the loop. One complete turn takes the circumference divided by the speed, so doubling the radius at fixed speed doubles the period while cutting the force in half. This is the relationship that determines how long a satellite takes to orbit and how fast a centrifuge needs to spin to reach a given acceleration.
Road engineering is a good illustration of how the formula is used in practice. A banked curve tilts the road so that a component of the normal force points toward the centre, supplying centripetal force without relying on friction. The banking angle is chosen for a design speed, and that is why a gently banked highway curve feels comfortable at one particular speed and nervous at twice it.
Centrifuges run the same arithmetic in reverse. Rather than asking what force a given motion needs, you ask what radius and speed produce a desired acceleration, and then spin the sample. Laboratory centrifuges routinely reach several thousand times gravity, and the calculation that decides the setting is exactly the acceleration term in this formula.
A final caution about direction that trips up drawings more often than arithmetic. The centripetal force is not tangential and it is not outward. On a free body diagram it should be drawn as an arrow from the object toward the centre of the circle, and confusing that with the tangential direction of motion produces a diagram that cannot be analysed at all.
Formula
F = m x v^2 / r
The inward force needed to maintain a circular path at constant speed.
| Symbol | Meaning | Unit | Notes |
|---|---|---|---|
| F | Centripetal force | newtons | Inward force in newtons. |
| m | Mass | kilograms | Mass of the moving object. |
| v | Speed | metres per second | Tangential speed along the path. |
| r | Radius | metres | Radius of the circular path. |
a = v^2 / r = omega^2 x r
The acceleration that goes with the force, always pointing at the centre.
| Symbol | Meaning | Unit | Notes |
|---|---|---|---|
| a | Centripetal acceleration | metres per second squared | Inward acceleration. |
| v | Speed | metres per second | Tangential speed. |
| omega | Angular velocity | radians per second | Rate of turning in radians per second. |
| r | Radius | metres | Radius of the path. |
T = 2 x pi x r / v
Time for one complete revolution, the circumference divided by the speed.
| Symbol | Meaning | Unit | Notes |
|---|---|---|---|
| T | Period | seconds | Time for one full turn. |
| pi | Pi | none | The circle constant, about 3.14159. |
| r | Radius | metres | Radius of the path. |
| v | Speed | metres per second | Tangential speed. |
How To Calculate A Centripetal Force
- 1
Get the mass in kilograms
Convert grams to kilograms by dividing by 1,000. A 150 gram mass is 0.15 kilograms, and forgetting this step overstates the answer by a factor of 1,000.
- 2
Square the speed
Multiply the speed by itself. Twelve metres per second squared is 144, and this is where the strong speed dependence enters.
- 3
Multiply by the mass
Multiply the squared speed by the mass. For 0.15 kilograms and 144 that is 21.6.
- 4
Divide by the radius
Divide by the radius in metres. Twenty-one point six divided by 0.8 gives 27 newtons, the inward force needed.
Examples
Example 1: A mass on a string
- Mass
- 150 g
- Tangential speed
- 12 m/s
- Radius
- 0.8 m
| Step | Calculation | Result |
|---|---|---|
| Mass in kilograms | m in kilograms | 150 / 1000 |
| Speed squared | v squared | 12 x 12 |
| Numerator | m x v squared | 0.15 x 144 |
| Centripetal force | F = 21.6 / 0.8 | 27 |
Result: The string needs to pull with 27 newtons, which is roughly the weight of a 2.75 kilogram mass hanging from it.
Example 2: A car on a flat curve
- Mass
- 1,200 kg
- Tangential speed
- 15 m/s
- Radius
- 60 m
| Step | Calculation | Result |
|---|---|---|
| Speed squared | v squared | 15 x 15 |
| Numerator | m x v squared | 1200 x 225 |
| Centripetal force | F = 270000 / 60 | 4500 |
Result: The tyres have to supply 4500 newtons of friction, which is about 0.38 times the car's weight on level road.
Example 3: How tight is the turn
- Mass
- 0.2 kg
- Tangential speed
- 6 m/s
- Radius
- 1.5 m
| Step | Calculation | Result |
|---|---|---|
| Speed squared | v squared | 6 x 6 |
| Numerator | m x v squared | 0.2 x 36 |
| Centripetal force | F = 7.2 / 1.5 | 4.8 |
| Halving the radius | F when the radius is halved | 9.6 |
Result: Halving the radius would double the required force to 9.6 newtons, because the radius sits in the denominator.
Calculator
Centripetal force
27
- Centripetal acceleration
- 180
- Angular velocity
- 15
- Revolution period
- 0.4189
Values update as you type. This calculator covers the single scenario its formula assumes — see Common Mistakes for what it leaves out.
Prefer a full-width tool? Open the A Centripetal Force calculator page.
Common Mistakes
Forgetting to square the speed
The velocity enters as v squared. Using v instead of v squared understates the force by a factor of v, which is usually an order of magnitude.
Using grams instead of kilograms
The formula assumes kilograms. A 150 gram mass entered as 150 overstates the force by 1,000 times.
Treating centripetal force as a separate force
It is whatever inward force exists. Tension, friction and gravity are the usual sources, and nothing new is added to the free body diagram.
Calling the force centrifugal
Centrifugal force is the outward sensation felt in the rotating frame. It is not a force in an inertial frame, and it points the opposite way.
Using diameter instead of radius
The radius is half the diameter. Using the full diameter halves the answer.
Expecting the speed to change
A centripetal force is perpendicular to the velocity, so it does no work and the speed stays constant. If the speed changes, there is a tangential component too.
FAQ
How do you calculate centripetal force?
Multiply the mass by the square of the speed and divide by the radius. A 0.15 kg mass at 12 m/s on a 0.8 m radius needs 27 newtons.
What is the difference between centripetal and centrifugal force?
Centripetal force is the real inward force keeping the object on a circle. Centrifugal force is the apparent outward push experienced inside the rotating frame, and it disappears in an inertial frame.
Why does the force grow with the square of the speed?
Because both the rate of direction change and the momentum being turned scale with the speed. Halving the speed cuts the required force to a quarter.
What supplies the centripetal force for a satellite?
Gravity. The satellite is continuously falling toward the planet but moving sideways fast enough that it keeps missing, which is what an orbit is.
Does centripetal force change the speed?
No. It is perpendicular to the motion, so it does no work. It changes only the direction, and the speed stays constant.
How is angular velocity related to centripetal force?
Since speed is angular velocity times radius, the force equals mass times angular velocity squared times radius. You can use either form as long as the units are consistent.
References
- [1]Wikipedia, Centripetal force — https://en.wikipedia.org/wiki/Centripetal_force
- [2]Khan Academy, Circular motion and centripetal acceleration — https://www.khanacademy.org/science/physics
- [3]Physics Classroom, Uniform circular motion — https://www.physicsclassroom.com/