Physics
How To Calculate The Period Of A Pendulum
A pendulum's period depends on just two things: how long it is and how strong gravity is. Neither the mass hanging on the end nor a small swing angle changes the answer.
Quick Answer
T = 2 x pi x sqrt(L / g)
- T
- The period, the time for one complete swing there and back
- L
- The length of the pendulum from pivot to centre of mass
- g
- The acceleration of gravity, 9.80665 m/s^2 at standard gravity
- pi
- About 3.14159, from the circular motion of the swing
Divide the length by gravity, take the square root, and multiply by two pi. A 1 metre pendulum gives 2.0064 seconds, which means 0.4984 swings per second and 29.9042 swings per minute.
What Is The Period Of A Pendulum?
The period of a simple pendulum is the time for one complete swing, out and back. The formula is two pi times the square root of the length divided by the acceleration of gravity.
The result is famously independent of mass. Hang a heavy bob or a light one at the same length and they swing together, because gravity pulls harder on the heavy one by exactly the factor that makes it harder to accelerate.
It is also independent of amplitude, at least for small swings. This is the isochronism Galileo noticed watching a lamp swing in a cathedral, and it is what made accurate clocks possible.
The small angle approximation is the fine print. The formula assumes the restoring force is proportional to the displacement, which holds to about a quarter of a percent at 10 degrees but drifts to roughly 1.7 percent slow at 30 degrees.
Only two inputs matter: length and gravity. Everything else, the bob's mass, the string's thickness, the material, drops out of the mathematics entirely.
Longer pendulums swing slower, but not proportionally. Doubling the length multiplies the period by the square root of two, which is 1.414214, so a 2 metre pendulum takes 2.8375 seconds against the 2.0064 of a 1 metre one.
A seconds pendulum is the classic special case. It takes exactly one second to swing each way, giving a two second period, and that needs a length of 0.993621 metres at standard gravity.
That number is why the metre was nearly defined by a pendulum. A one second swing is so close to a metre that the two were proposed as the same standard, before the Earth proved too irregular.
Gravity genuinely varies across the Earth's surface. It is about 9.780 at the equator and 9.832 at the poles, so a pendulum clock calibrated in one place runs slow or fast in another by a fraction of a percent.
Pendulums were the best way to measure gravity for two centuries. Kater's reversible pendulum turned the formula around and read g off a measured period to five significant figures.
Clock makers had to deal with thermal expansion. A steel rod grows with temperature, the period lengthens, and the clock loses time, which is why compensation pendulums using two metals were invented.
The formula describes a simple pendulum: a point mass on a weightless string. A real swinging rod is a compound pendulum, and its period depends on how its mass is distributed as well as its length.
Angular frequency is the square root of gravity over length. For a 1 metre pendulum that is 3.1316 radians per second, and the ordinary frequency is that divided by two pi, which is 0.4984 hertz.
On the Moon, where gravity is about a sixth of Earth's, the same pendulum swings roughly two and a half times slower. Nothing about the pendulum changed, only g.
For a 1 metre pendulum at standard gravity the period is 2.0064 seconds, close enough to two seconds that the approximation is worth memorising.
Formula
T = 2 x pi x sqrt(L / g)
Formula page →The small angle result, depending only on length and gravity.
| Symbol | Meaning | Unit | Notes |
|---|---|---|---|
| T | Period | seconds | The time for one complete swing. |
| L | Length | metres | The distance from the pivot to the centre of mass. |
| g | Gravity | metres per second squared | The local acceleration of gravity. |
f = 1 / T, and omega = sqrt(g / L)
Formula page →The same motion described as swings per second and as radians per second.
| Symbol | Meaning | Unit | Notes |
|---|---|---|---|
| f | Frequency | hertz | The number of complete swings per second. |
| omega | Angular frequency | radians per second | The same rate in radians per second. |
| T | Period | seconds | The time for one complete swing. |
L = g x T^2 / (4 x pi^2)
Formula page →Inverts the formula, which is how a pendulum clock is set up.
| Symbol | Meaning | Unit | Notes |
|---|---|---|---|
| L | Length | metres | The length that gives the wanted period. |
| T | Target period | seconds | The period you want the pendulum to have. |
| g | Gravity | metres per second squared | The local acceleration of gravity. |
How To Calculate The Period Of A Pendulum
- 1
Divide the length by gravity
One metre divided by 9.80665 is 0.101972 seconds squared. Keeping the units straight here is what makes the square root come out in seconds.
- 2
Take the square root
The square root of 0.101972 is 0.31933 seconds. This is the time scale of the swing, and it grows with the square root of the length.
- 3
Multiply by two pi
0.31933 times 6.283185 is 2.0064 seconds, the period of a 1 metre pendulum. Roughly two seconds, which is a useful rule of thumb.
- 4
Cross check against the seconds pendulum
A two second period needs a length of 0.993621 metres, just six millimetres short of a metre. If your answer is far from that, a unit conversion went wrong.
Examples
Example 1: A 1 metre pendulum at standard gravity
- Pendulum length
- 1
- Gravity
- 9.80665
| Step | Calculation | Result |
|---|---|---|
| Length over gravity | 1 / 9.80665 | 0.101972 |
| Square root | sqrt(0.101972) | 0.31933 |
| Period | 6.283185 x 0.31933 | 2.0064 |
| Swings per minute | 60 / 2.0064 | 29.9042 |
Result: A 1 metre pendulum has a period of 2.0064 seconds, which is 29.9042 complete swings a minute. Its frequency is 0.4984 hertz and its angular frequency is 3.1316 radians per second.
Example 2: Doubling the length to 2 metres
- Pendulum length
- 2
- Gravity
- 9.80665
| Step | Calculation | Result |
|---|---|---|
| Expected ratio | sqrt(2) | 1.414214 |
| Length over gravity | 2 / 9.80665 | 0.203943 |
| Period | 2.0064 x 1.414214 | 2.8375 |
| Frequency | 1 / 2.8375 | 0.3524 |
Result: Doubling the length multiplies the period by 1.414214, so a 2 metre pendulum takes 2.8375 seconds and swings 0.3524 times a second. Four times the length would double the period to 4.0128 seconds.
Calculator
Period
2.0064
- Frequency
- 0.4984
- Angular frequency
- 3.1316
- Swings per minute
- 29.9042
- Length of a seconds pendulum
- 0.9936
Values update as you type. This calculator covers the single scenario its formula assumes — see Common Mistakes for what it leaves out.
Prefer a full-width tool? Open the The Period Of A Pendulum calculator page.
Common Mistakes
Leaving the length in centimetres
The formula expects metres. Entering 100 for a metre long pendulum gives a period of 20.064 seconds, ten times too long.
Forgetting the square root
The period grows with the square root of the length, not with the length. Skipping the root makes a 2 metre pendulum look four times slower instead of 1.414214 times.
Putting the mass in the formula
Mass does not appear. A heavy bob and a light one at the same length swing together, because the extra gravitational force is cancelled by the extra inertia.
Trusting the formula at large angles
The small angle approximation degrades with amplitude. At 30 degrees the real period is about 1.7 percent longer than the formula predicts.
Confusing one swing with one period
A period is a full there and back cycle. A seconds pendulum takes one second each way and two seconds for a complete period.
Measuring to the wrong point
The length runs from the pivot to the centre of mass of the bob, not to the bottom of the bob or the end of the string.
FAQ
What is the formula for the period of a pendulum?
Two pi times the square root of the length divided by gravity. A 1 metre pendulum at standard gravity gives 2.0064 seconds.
Does the mass of the bob affect the period?
No. Mass cancels out of the equation of motion, so a heavy bob and a light one on the same length swing in step.
What is a seconds pendulum?
One that takes exactly one second to swing each way, giving a two second period. At standard gravity that needs a length of 0.993621 metres.
Why does my pendulum swing slower than the formula says?
Most often because the swing is large. The small angle approximation breaks down above about 10 degrees, and air resistance and a heavy string pull the period out as well.
What happens if I double the length?
The period multiplies by the square root of two, 1.414214, not by two. To double the period you need four times the length.
Does the formula work on the Moon?
Yes, with the local gravity. Lunar gravity is about a sixth of Earth's, so the same pendulum swings roughly two and a half times slower.
References
- [1]Wikipedia, Pendulum — https://en.wikipedia.org/wiki/Pendulum
- [2]Wikipedia, Simple harmonic motion — https://en.wikipedia.org/wiki/Simple_harmonic_motion
- [3]Wikipedia, Seconds pendulum — https://en.wikipedia.org/wiki/Seconds_pendulum